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The BODMAS mathematical rule.

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GoSeigen
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Re: The BODMAS mathematical rule.

#187513

Postby GoSeigen » December 17th, 2018, 5:57 pm

XFool wrote:
But in this instance that isn't the "howler" modellingman was alluding to. Rather it was the obvious mistake, in the working out, of describing
6/2*3 = 3/3.

Which should instead have been(?) described as either: 3*3 = 9 or 6/6 = 1(?)

Not if we are consistent in reading the "/" as the horizontal line separating numerator and denominator. In that case 2*3 forms the denominator. Here is 6/2*(2+1) =6/2*3=3/3 =1 laid out as Dod is imagining it:

.  6           6         3
------- = ------- = --- = 1
2*(2+1) 2*3 3


Note 1, that when laid out as above, it is not necessary to surround the denominator with brackets: it is evaluated before the whole fraction is evaluated even without the brackets.
Note 2, that I don't think that doing things this way is a good idea, it's just that I sympathise with the [Dod] interpretation if the context is either unknown or implies it.

...
Dod101 wrote:...but you could have done 6/2*(2+1) =6/2*3=3/3 =1 in strict accord with the BODMAS rules.


GoSeigen wrote:Then the 3/3 simply results from dividing by two in both the numerator and denominator.

Oh right!


Hopefully you see it now... can be hard to step in others' shoes sometimes!!

GS


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